Question

Va rog ajutați-mă rapid(8a,b,c,d)

Answer 1

Explicație pas cu pas:

${3}^{18} + {3}^{17} = 3 \cdot {3}^{117} + {3}^{17} = {3}^{17} \cdot (3 + 1) = \bf 4 \cdot {3}^{17}$

${2}^{29} + {2}^{27} - {2}^{26} = {2}^{26} \cdot ( {2}^{3} + 2 - 1) = {2}^{26} \cdot (8 + 2 - 1) = 9 \cdot {2}^{26} = 9 \cdot {2}^{2 \cdot 13} = 9 \cdot {( {2}^{2} )}^{13} = \bf 9 \cdot {4}^{13}$

${5}^{26} + {5}^{25} - {15}^{24} : {3}^{24} = {5}^{26} + {5}^{25} - {(3 \cdot 5)}^{24} : {3}^{24} = {5}^{26} + {5}^{25} - ({3}^{24} \cdot {5}^{24}) : {3}^{24} = {5}^{26} + {5}^{25} - {5}^{24} = {5}^{24} \cdot ( {5}^{2} + 5 - 1) = {5}^{24} \cdot (25 + 5 - 1) = 29 \cdot {5}^{24} = 29 \cdot {( {5}^{2} )}^{12} = \bf 29 \cdot {25}^{12} =$

${49}^{11} : {7}^{11} + {7}^{13} : 7 = {(49 : 7)}^{11} + {7}^{12} = {7}^{11} + {7}^{12} = {7}^{11} \cdot (1 + 7) = \bf 8 \cdot {7}^{11}$