Question

va rog ajutati ma sa inteleg si eu​

Answer 1

Inmultim mezii cu extremii . ( adica inmultim pe diagonala )

(x²+4x)/6=(2x+3)/3

3(x²+4x)=6(2x+3)

3x²+12x=12x+18

3x²=18

x²=6

x=√6

(x+1)/2=9/(x+1)

(x+1)²=18

x+1=√18

x+1=3√2

x=3√2-1

Answer 2

e.

(x²+4x)/6=(2x+3)/3

3(x²+4x)=6(2x+3)

3x²+12x=12x+18

3x²-18=12x-12x

3x²-18=0 | +18

3x² = 18 | : 3

x² = 6

=> x = ±√6 => S={-√6;√6}

f.

(x+1)/2=9/(x+1)

(x+1)(x+1)=2*9

(x+1)²=18

x+1=±√18

x+1=±3√2

=> x=3√2-1

sau x=-3√2-1

=> S={3√2-1;-3√2-1}

Succes.