Question

va rog ajutați mă!!! urgent dau coroana!​

Answer 1

Răspuns:

a)

4$\sqrt{3}$*$\sqrt{2}$ = 4$\sqrt{6}$

$5\sqrt{2} * \sqrt{3} = 5\sqrt{6}$

$4\sqrt{6}<5\sqrt{6} => 4\sqrt{3} <5\sqrt{2}$

b)

$-6\sqrt{3} *\sqrt{7}= -6\sqrt{21} \\-4\sqrt{7}*\sqrt{3} = -4\sqrt{21} \\-6\sqrt{21} <-4\sqrt{21} => -6\sqrt{3} < -4\sqrt{7}$

c)

$5\sqrt{3} *\sqrt{2} = 5\sqrt{6} \\6\sqrt{2}*\sqrt{3} = 6\sqrt{6} \\5\sqrt{6} <6\sqrt{6} => 5\sqrt{3} <6\sqrt{2}$

d)

$4-2\sqrt{5} = 4- 2*\sqrt{5} =4-2*2,23=4-4, 46 = -0,46\\-0, 46 < 0 => 4-2\sqrt{5} <0$

e)

$7-5\sqrt{2} = 7- 5*\sqrt{2} = 7-5*1,41 = 7-7,05=-0,05\\-0,05<0 => 7-5\sqrt{2} <0$

f)

$5-3\sqrt{3} = 5-3*1,73 = 5-5,19=-0,19\\2\sqrt{3} = 2*1,73 = 3,46\\-0,19<3,46 => 5-3\sqrt{3} < 2\sqrt{3}$