Question

va rog ajutati.ma vreau cu desfasurarea(adica nu vreau raspunsul direct)HELP ME DAU 20 DE PUNCTE

Answer 1

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Answer 2

[tex]\it 7^{120} : 49^{60} +8^{30}:16^{22} +100^{20}:10^{38} -7\cdot3\cdot5 = \\\;\\ =7^{120} :(7^2)^{60} +(2^3)^{30}:(2^4)^22+(10^2)^{20}:10^{38} -103 = [/tex]

[tex]\it = 7^{120}:7^{120} +2^{90}:2^{88} +10^{40}:10^{38} -105 = \\\;\\ = 1+4+100-105 = 0 [/tex]