Question

va rog ajutati-maaa !!!
Dau 25 puncte si coronita si multumesc !!!
n.634-[(206x4-618:3):3]x2
o.[(3+3)x3-3+3x(3+3:3)]:3-3x3+3:3x1+3:1
p.9+8x[7+6x(5+4x3)-2]-10x10
q.401-603:3+[330:3+2x(0:99+2x40)]:9
r.(36:4+4x6+8:2+2):[(36:4+3x13)-3x10-15 .
va rogggg

Answer 1

n)634-[(206x4-618:3):3]·2
634-[(206·4-618:3):X]·2=222
[(824-206):X]·2=634-222⇒412
(618:X)=412:2
618:X=206
X=618:206
X=3

o)[(3+3)·3-3+3·(3+3:3)]:3-3·3+3:3·1+3:1
[6·3-3+3·4]:3-9+1+3=
[18-3+12]:3-9+1+3=
27:3-9+1+3=
9-9+1+3=
0+1+3=4
p)9+8·[7+6·(5+12)-2]-10·10=
9+8·[7+6·17-3]-10·10=
9+8·[7+102-3]-10·10=
9+8·106-10·10=
9+848-100=757
q)401-603:3+[330:3+2·(0:99+2·40)]:9
401-603:3+[330:3+2·(0+80)]:9=
401-603:3+[110+160]:9=
401-603:3+270:9=
401-201+30=230
r)(36:4+4·6+8:2+2):[(36:4+3·13)-3·10-15]
(9+24+4+2):[(9+39)-30-15]=
39:(48-45)=
39:3=
13

Answer 2

n)634-[(824-206)÷3]×2=
634-[618÷3]×2=
634-206×2=
634-412=222
o)[6×3-3+3×4]÷3-9+1+3=
[18-3+12]÷3-9+4=
27÷3-5=
9-5=4
p)9+8×[7+6×(5+12)-2]-100
9+8×[7+6×17-2]-100=
9+8×[7+102]-100=
9+8×109-100=
9+872-100=
881-100=781
q)401-201+[110+2×(0+80)]÷9=
401-201+[110+2×80]÷9=
401-201+270÷9=
401-201+30=230
r)(9+24+4+2)÷[(8+38)-30-15.....aici unde se inchidevparanteza patrata?