Question

Va rog ajutati-ne
Calculati cantitatea (in moli,g,l) de H2 necesar reducerii a 8g CUO de puritate 80%
Va multumim

Answer 1

-calculez masa de Cu O pur
p= m,px100/ m,impur
80/100= m,pur/8----> m,pur= 6,4g CuO pur-   M(miu)= (64gCu+16gO)mol

-calculez  moli si masa H2 necesar in reactie
1mol       1mol        
CuO +   H2---> Cu+ H2O
80g.........1mol
6,4g.........x----> x=0,08molH2

m,H2= n,molxM,g/mol=> m= 0,08molx2g/mol=...................CALCULEAZA !!!