Question

va rog ajutatima.......

Answer 1

2intreg 1/3=(2x3+1)/3=7/3
Mp=[(2,5x2+7/3x3+4x5)/(2+3+5)=(5+7+20)/10=32/10=3,2

b) 0,(3)=3/9=simplif=1/3
0,1(6)=(16-1)/90=15/90=simplif.cu5=3/18=simplif cu 3=1/6
0,(4)=4/9
Mp=(1/3x3+1/6x15+4/9x9)/(3+15+9)=(1+15/6+4)/27=(5+15/6)/27=
=[5x6+15)/6]/27=(45/6)/27=45/(6x27)=45/162=0,2(7)

c)2,(3)=(23-2)/9=21/9=7/3
2intreg7/3=13/3
3,(6)=(36-3)/9=33/9=11/3
Mp=(6/7x7/3+9/8x13/3+5/3x3/1+3/11x11/3)/(7/3+13/3+11/3+3/1)=
=(2+39/8+5+1)/(31/3+3)=[(8+39/8)]/[(31+3x3)/3]=
=[(8x8+39)/8]/(40/3)=(103/8)/(40/3)=103/8:40/3=103/8x3/40=309/240=1,2875