Question

Va rog ajutatima (2√2)^2+2√2(2-√2)+2

Answer 1

Aici ai rezolvarea.
Sper ca te-am putut ajuta :)

Answer 2

${(2 \sqrt{2}) }^{2} + 2 \sqrt{2}(2 - \sqrt{2}) + 2 = \\ \\ {2}^{2} { \sqrt{2} }^{2} + 2 \sqrt{2}(2 - \sqrt{2}) + 2 = \\ \\ 4 { \sqrt{2} }^{2} + 2 \sqrt{2}(2 - \sqrt{2}) + 2 = \\ \\ 4 \times 2 + 2 \sqrt{2}(2 - \sqrt{2}) + 2 = \\ \\ 8 + 2 \sqrt{2}(2 - \sqrt{2}) + 2 = \\ \\ (8 + 2) + 2 \sqrt{2}(2 - \sqrt{2}) = \\ \\ 10 + 2 \sqrt{2}(2 - \sqrt{2}) = \\ \\ 10 + 4 \sqrt{2} - 4 = 6 + 4 \sqrt{2}$