Question

Va rog ajutatima???????????

Answer 1

Răspuns:

Explicație pas cu pas:

Mult succes!

Answer 2

$\displaystyle \left|\begin{array}{ccc}x-3&5\\-4&x\end{array}\right|+\left|\begin{array}{ccc}5x&3\\4&2\end{array}\right| -7x \cdot \left|\begin{array}{ccc}8&3\\5&2\end{array}\right|=44 \\ \\ (x-3) \cdot x-5 \cdot (-4)+5x \cdot 2-3 \cdot 4-7x\cdot (8 \cdot 2-3 \cdot 5)=44\\ \\ x^2-3x+20+10x-12-7x \cdot (16-15)=44\\\\x^2+7x+8-7x \cdot 1=44 \\ \\x^2+7x+8-7x=44\\ \\x^2+8=44\\ \\x^2=44-8\\\\x^2=36\Rightarrow x_1=\sqrt{36} \Rightarrow x_1=6\\\\~~~~~~~~~~~\Rightarrow x_2=-\sqrt{36} \Rightarrow x_2=-6\\\\S=\{-6;6\}$