Question

Va rog ajutatima. Datele sunt cele din poza, imi cere BC.

Answer 1

Se aplica teorema sinusurilor :$\frac{BC}{sinA}= \frac{AB}{sinC}= \frac{AC}{sinB},deci, \frac{BC}{sin45}= \frac{ \sqrt{3} }{sin30},rezulta,BC= \sqrt{3} \frac{ \sqrt{2} }{2}: \frac{1}{2}= \sqrt{6}$