Question

va rog ajutatima dau coroana si multe puncte​

Answer 1

Rezolvare

{1^20 +[2^10 :2^7 - 4^1 ×(7^5:7^4-6^1)]}:3^0=

{1 +[2^(10-7)-4 ×(7^(5-4)-6)]} :1=

{1 +[2^3-4×(7-6)]}:1=

[1+(8-4×1)]:1=

[1+(8-4)]:1=

(1+4):1=

5:1=

5

Răspuns :5

Answer 2

Răspuns: 5

Explicație pas cu pas:

$\displaystyle\bf\\(1^{20} + (2^{10} : 2^{7} - 4^{1} * (7^{5} :7^{4} -6^{1}) ) ):3^{0} \\\\(1 + (2^{10-7}- 4 * (7^{5-4} -6) ) ):1\\\\(1 + (2^{3}- 4 * (7^{1} -6) ) )\\\\(1 + (8- 4 * (7-6) ) )\\\\ 1 + 8 - 4 * 1\\\\9-4\\\\\boxed{5}$