Question

va rog ajutatima la exercitiul 7 (a,b,c,d,e,f,g) si 8 (a,b,c,d,e,f).

Answer 1

7.
a)(14-5)/3=9/3=3
b)Numitor comun 6 : (4+3)/6=7/6=1 intreg 1/6
c)Numitor comun 10 : (-65+2)/10=(-63)/10=-6,3
d)0,(3)=3/9=1/3
1/3 - 1/3 = 0
e)(10-11)/2=(-1)/2=-0,5
f)7·2,2-1=15,4-1=14,4
g)34,6-34,6=0

8.
a)√2(5+8)=13√2
b)√2(1+1+1)=3√2
c)√3(1+1+1)=3√3
d)√3(7-6)=√3
e)2+7=9 (cei doi radicali sunt aceiasi, doar ca au semne diferite, deci se reduc)
f)√3(-4-8)=-12√3