Question

VA rog ajutatima la paranteze

Answer 1

$(5+ \frac{2}{3})( \frac{5}{17}+ \frac{1}{2})*1 \frac{2}{3}- \frac{5}{9}= \\ \\ ( \frac{5*3+2}{3})( \frac{5*2+17}{17*2})* \frac{1*3+2}{3}- \frac{5}{9}= \\ \\ \frac{10}{3}* \frac{27}{34}* \frac{5}{3}- \frac{5}{9}= \\ \\ \frac{75}{17}-\frac{5}{9}= \\ \\ \frac{75*9}{17*9}-\frac{5*17}{9*17}= \\ \\ \frac{675-85}{153} = \\ \\ =\frac{590}{153}$

$\frac{3}{8}[ \frac{1}{4}+( \frac{7}{36}- \frac{1}{24}): \frac{7}{6}]= \\ \\ \frac{3}{8}[ \frac{1}{4}+( \frac{7*2}{72}- \frac{1*3}{72}): \frac{7}{6}]= \\ \\ \frac{3}{8}[\frac{1}{4}+( \frac{9}{72}}): \frac{7}{6}]= \\ \\ \frac{3}{8}[\frac{1}{4}+ \frac{1}{8}}: \frac{7}{6}]= \\ \\ \frac{3}{8}(\frac{1}{4}+ \frac{1}{8}}* \frac{6}{7})= \\ \\ \frac{3}{8}(\frac{1}{4}+ \frac{3}{28}})= \\ \\ \frac{3}{8}(\frac{1*7+3}{28}})= \\ \\ \frac{3}{8}*\frac{10}{28}}= \\ \\ = \frac{15}{28}$

$\frac{2}{7}*[( \frac{1}{3}+ \frac{7}{15} - \frac{1}{5})* \frac{5}{4} +(\frac{1}{2}- \frac{1}{4} ): \frac{5}{12}]= \\ \\ \frac{2}{7}*[( \frac{5}{15}+ \frac{7}{15} - \frac{3}{15})* \frac{5}{4} +(\frac{2-1}{4} )* \frac{12}{5}]= \\ \\ \frac{2}{7}*( \frac{9}{15}* \frac{5}{4} + \frac{1}{4} * \frac{12}{5})= \\ \\ \frac{2}{7}*( \frac{15}{4} + \frac{3}{5})= \\ \\ \frac{2}{7}*( \frac{15*5+3*4}{20} )= \\ \\ \frac{2}{7}*( \frac{75+12}{20} )= \\ \\ \frac{2}{7}* \frac{87}{20}= \\ \\ =\frac{87}{70}$

Answer 2

Numai controleaza daca inceputul e corect scris