Question

Va rog ajutatima √mare din (2-√5)totu la patrat+√are din (3√3-6)totu la patrat+√mare din (-√5+1)totu la patrat

Answer 1

$\it \sqrt{(2-\sqrt5)^2} +\sqrt{(3\sqrt3-6)^2}+\sqrt{(-\sqrt5+1)^2} =|2-\sqrt5| +|3\sqrt3-6| + \\ \\ +|-\sqrt5+1| = \sqrt5-2+6-3\sqrt3 +\sqrt5-1 =2\sqrt5-3\sqrt3+3$

Answer 2

Cand avem ceva ridicat la patrat sub radical va ramane modul.
|2-√5| + |3√3 - 6| + |-√5 + 1| =
= -(2-√5) + [-(3√3 - 6)] + [-(-√5 + 1)] =
= √5 -2 + 6 -3√3 +√5 -1 =
= 2√5 - 3√3 + 3