Question

Va rog ajutatima ofer 30 pucte daca imi rezolvati macar cat va din tema din teorema lui pitagora si reciproca teorema lui pitagora
1) Fie ABC un triunghi dr. in A. Calculati lungimea celei de-a treia laturi a tiunghiului ABC,stind ca:
A)AB=2dm,AC=radical din 5
B)AC=6dam,BC=10dam
C)AB=5m,AC=12m
D)AB=5mm,BC=7mm

Answer 1

a) AB=2dm =20 cm
AC= √5 cm
BC=?
In ∆ABC dr=>T. P AB²+ AC²=BC²
20²+√5²=BC²
BC² = 400+√25
BC²=400+5
BC ²= 405
BC=√405
BC=9√5 cm

b)
AC=6dam= 6000cm
BC=10dam= 10000 cm
In ∆ABC dr=>T. P AB²+ AC²=BC²
AB²+6000²= 10000²
AB²=10000²-6000²
AB²=640000
AB=√640000
AB=8000 cm

C)AB=5m=500 cm
AC=12m= 1200 cm
In ∆ABC dr=>T. P AB²+ AC²=BC²
500²+1200²=BC²
BC²= 1690000
BC= √1690000
BC = 1300 cm

D)AB=5mm=50 cm
BC=7mm=70 cm
In ∆ABC dr=>T. P AB²+ AC²=BC²
50²+AC²=70²
AC²= 70²-50²
AC²= 4900-2500
AC²=2400
AC=√2400
AC= 20√6