Question

va rog ajutatiman
rezolvati in R ecuatia:2(3x-2)+3(4-2x)

Answer 1

2(3x-2)+3(4-2x)=(6x-4)+(12-6x)=6x-4+12-6x=12x=-16
x=$\frac{-16}{12} ^{(4}$
x=$\frac{-4}{3}$   sau x=$1 \frac{1}{3}$