Question

va rog ajutor:
8x[30-(27+5x):7+6]=120
24+[72-(y-3)x10+4]:2=32

Arata ca ax5=b stiind ca:
a=38:2+[2x25-(15-320:40)x4]:11
b=9x15-[25-(32:8x3+40x7:10):2]x6

Answer 1

$a = 19 + (50 - 7 \times 4) \div 11 \\ \: \: \: \: = 19 + (50 - 28) \div 11 \\ \: \: \: \: = 19 + 22 \div 11 = 19 + 2 = > a = 21$
$b = 135 - [25 - (12 + 28) \div 2] \times 6 = 135 - (25 - 40 \div 2) \times 6 = 135 - (25 - 20) \times 6 = 135 - 5 \times 6 =135 - 30 = > b = 105$
$a = 19 + (50 - 7 \times 4) \div 11 \\ \: \: \: \: = 19 + (50 - 28) \div 11 \\ \: \: \: \: = 19 + 22 \div 11 = 19 + 2 = > a = 21$
$a \times 5 = b = > 21 \times 5 = 105 \: (adevarat)$