Matematică, întrebare adresată de Anisuca7, 8 ani în urmă

VA ROG!! AJUTOR! dau coroană ​

Anexe:

Răspunsuri la întrebare

Răspuns de agavriloaelidia3
2

Răspuns:

te rog să copii tot

totul este corect

Anexe:

Anisuca7: mulțumesc!
Răspuns de stancescuflorin741
1

Răspuns:

a )\frac{x}{1.2}  =   \frac{( {2.5 - 1 \frac{2}{3} })^{2} }{ \frac{5}{24} }   \\  \frac{x}{1.2}   = \frac{( \frac{25}{10}  -  \frac{1 \times 3 + 2}{3}) ^{2}  }{ \frac{5}{24} }  \\  \frac{x}{1.2}  =  \frac{ (\frac{ {25} }{10} -  \frac{5}{3}  ) ^{2} }{ \frac{5}{24} }  \\  \frac{x}{1.2}  =  \frac{( \frac{25 \times 3}{30}  -  \frac{5 \times 10}{30}) ^{2}  }{ \frac{5}{24} }  \\  \frac{x}{1.2}  =  \frac{ (\frac{75}{30} -  \frac{50}{30}  ) ^{2} }{ \frac{5}{24} }  \\  \frac{x}{1.2}  =  \frac{ (\frac{ {25} }{30}) ^{2}  }{ \frac{5}{24} }  \\  \frac{x}{1.2}  =  \frac{ \frac{625}{900} }{ \frac{5}{24} }  \\  \frac{x}{1.2}  =  \frac{625}{900}  \div  \frac{5}{24}  \\  \frac{x}{1.2}  =  \frac{625}{900}  \times  \frac{24}{5}  \\  \frac{x}{1.2}  =  \frac{125}{150}  \times  \frac{4}{1}  \\  \frac{x}{1.2}  =  \frac{600}{150}  \\  \frac{x}{1.2}  = 4 \\ x = 1.2 \times 4 = 4.8

b) \frac{8  \frac{8}{15}  \times ( \frac{1}{5} + x \times (1 \frac{1}{3} - 1 \frac{1}{5} )) \times 1 \frac{2}{3}   }{2.1(3)}  =  \frac{ {16}^{8} }{ {8}^{10} }  \\  \frac{ \frac{8 \times 15 + 8}{15}  \times ( \frac{1}{5} +  x \times( \frac{1 \times 3 + 1}{3} -  \frac{1 \times 5 + 1}{5}  )) \times  \frac{1 \times 3 + 2}{3}   } {2.1(3)}  =  \frac{ {16}^{8} }{ {8}^{10} }  \\  \frac{ \frac{128}{15}  \times ( \frac{1}{5} + x \times ( \frac{4}{3}   -  \frac{6}{5} )) \times  \frac{5}{3} }{2.1(3)}  =  \frac{ {16}^{8} }{ {8}^{10} }  \\  \frac{ { \frac{128}{15} \times ( \frac{1}{5}  + x \times ( \frac{4 \times 5}{15} -  \frac{6 \times 3}{15}) \times  \frac{5}{3}    } }{2.1(3)} =  \frac{ {16}^{8} }{ {8}^{10} }  \\  \frac{ \frac{128}{15} \times ( \frac{1}{5}   + x \times  \frac{2}{15} \times  \frac{5}{3}  )}{2.1(3)}  =  \frac{ {16}^{8} }{ {8}^{10} }  \\  \frac{ \frac{128}{15} \times (  \frac{1}{5} +  \frac{10x}{45} ) }{2.1(3)}  =  \frac{ {16}^{8} }{ {8}^{10} }  \\  \frac{ \frac{128}{15} \times ( \frac{9}{45} +  \frac{10x}{45} )  }{2.1(3)}  =  \frac{ {16}^{8} }{ {8}^{10} }  \\  \frac{ \frac{128}{15}  \times  \frac{9 + 10x}{45} }{2.1(3)}  =  \frac{ {16}^{8} }{ {8}^{10} }  \\


Anisuca7: mulțumesc!
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