Question

Va rog ajutor dau coroana de la III roman 1 si 2

Answer 1

1. Kc = [CO]×[Cl₂]/[COCl₂] = (0,0456×0,0456)/0,449 = 0,004631 = 4,63×10⁻³ mol/L 

2. Kc = [H₂]²×[O₂]/ [H₂O]² ⇔ 2,4×10⁻³ = (1,9*10⁻²)²×[O₂] / (1,1×10⁻¹)² ⇔ 2,4*10⁻³×(1,1×10⁻¹)² = (1,9×10⁻²)²×[O₂] ⇔ 2,904×10⁻⁵ = 36,1×10⁻⁵[O₂] ⇒ [O₂] = (2,904×10⁻⁵)/(36,1×10⁻⁵) = 0,08 = 8×10⁻² moli/L