Question

Va rog ajutor dau coronita

Answer 1

Răspuns:

Să se calculeze:

$( {3}^{7} ) {}^{6} \times {3}^{2} \div {3}^{41 } - {5}^{2} \\ = {3}^{42} \times {3}^{2} \div {3}^{41} - {5}^{2}$

$= 3 {}^{42 + 2} \div 3 {}^{41} - 5 {}^{2} \\ = 3 {}^{44} \div 3 {}^{41} - 5 {}^{2} \\ = {3}^{44 - 41} - 5 {}^{2} \\ = {3}^{3} - {5}^{2} \\ = 27 - 25 = 2$