Question

Va rog ajutor exercitiul 34

Answer 1

intersectia cu Ox, 0=-4x/3+4 ⇒ x=3 ⇒  P(0,3), P∈Gf
intersectia cu Oy, f(0)=4 ⇒ A(0,4), A∈Gf
M(-2,0)
 [MP]=b=2+3=5
f(-2)=20/3, N(-2,20/3), ⇒ MN=20/3
pitagora ⇒ PN=√(MP^2+MN^2)=√(25+400/9)
PN=25/3
ducem MD⊥NP
aria MNP in 2 moduri ⇒ NP x MD=MP x MN
MD=MP x MN/NP=4 ⇒ d(M;Gf)=MD=4