Question

va rog ajutor!!! îmi trebu urgent ​

Answer 1

Explicație pas cu pas:

$\dfrac{2x^{(x}}{7 {x}^{2} } = \dfrac{2}{7x}$

$\dfrac{x^{(x}}{{x}^{2} } = \dfrac{1}{x}$

$\dfrac{3x(x + 2)^{(3(x + 2)}}{9{(x + 2)}^{2} } = \dfrac{x}{3(x + 2)}$

$\dfrac{11 {{x}^{2}} ^{(x}}{2ax} = \dfrac{11x}{2a}$

$\dfrac{4{ {x}^{3} }^{( 2{x}^{3} }}{6 {x}^{4} } = \dfrac{2}{3x}$

$\dfrac{ {x}^{2} + x}{3x + 3} = \dfrac{x(x + 1) ^{(x + 1} }{3(x + 1)} = \dfrac{x}{3}$

$\dfrac{ {x}^{2} - 25}{x + 5} = \dfrac{(x - 5)(x + 5) ^{(x + 5} }{x + 5} = x - 5$