Question

Va rog ,ajutor la acest ex :.........Multumesc!

Answer 1

Răspuns:

x³-3x²-3x+1=0

(x³+1)-3x(x+1)=0

(x+1)(x²-x+1)-3X(x+1)=0

(x+1)(x²-x+1-3x)=0

x+1=0

x1=-1

(x²-4x+1=0

Δ=4²-4=0

Δ=16-4=12

x2=(4-√Δ)/2=(4-√12)/2=(4-2√3)/2=(2-√3)

x3=(4+√Δ)/2=...=2+√3

2*(-1)+(2-√3)(2+√3)=

-2+4-3= -1

Explicație pas cu pas: