Question

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Answer 1

[tex]\tt Se~da: \\ \\ V_{1}=0,1l=0,0001m^{3}\\ \\ \rho_{1}=1000\frac{kg}{m^{3}}(Sint~sigur~ca~e~1000~nu~100)\\ \\ V_{2}=500cm^{3}=0,0005m^{3}\\ \\ \rho_{2}=800\frac{kg}{m^{3}}\\ \\ \rho=?\frac{kg}{m^{3}}\\ \\ \\ Formule:\\ \\ \rho=\frac{m}{V}\\ \\ \rho=\frac{m_{1}+m_{2}}{V_{1}+V_{2}}\\ \\ \rho=\frac{V_{1}\times\rho_{1}+V_{2}\times\rho_{2}}{V_{1}+V_{2}}\\ \\ \\ Calcule:\\ \\ \rho=\frac{0,0001\times1000+0,0005\times800}{0,0001+0,0005}=833,(3)\frac{kg}{m^{3}}\\ \\[/tex]





[tex]\tt Se~da: \\ \\ G=5N\\ \\ l=5cm=0,05m\\ \\ g=10\frac{N}{kg}\\ \\ \rho=?\frac{kg}{m^{3}}\\ \\ \\ Formule:\\ \\ \rho=\frac{m}{V}\\ \\ \\ G=m\times g\\ \\ m=\frac{G}{g}\\ \\ \\ V=l^{3}\\ \\ \\ \rho=\frac{G}{g \times l^{3}}\\ \\ \\ Calcule:\\ \\ \rho=\frac{5}{10 \times 0,05^{3}}=4000\frac{kg}{m^{3}}[/tex]