Question

va rog, ajutor!
Sa se simplifice prin 5 numerele:
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Answer 1

$\frac{10}{15} = \frac{2}{3} \\ \frac{15}{45} = \frac{3}{9} \\ \frac{5a}{10b} = \frac{a}{2b} \\ \frac{10a + 10b}{25x + 25y} = \frac{2a + 2b}{5x + 5y} \\ \frac{2 {}^{2} \times 5 } {3 \times 5} = \frac{4 \times 5}{3 \times 5 } = \frac{20}{15} = \frac{4}{3}$

mi-a luat ceva dar sper ca totul este in regula

Answer 2

$\frac{ {10}^{(5} }{15} = \frac{2}{3} = > fractie \: ireductibila$

$\frac{ {15}^{(5} }{45} = \frac{ {3}^{(3} }{9} = \frac{1}{3}$

$\frac{5a {}^{(5} }{10b} = \frac{a}{b}$

$\frac{10a + 10b{}^{(5} }{25x + 25y} = \frac{ {2a + 2b}^{} }{5x + 5y}$

$\frac{ {2}^{2} \times 5 {}^{(5} }{3 \times 5} = \frac{4}{3} =$