Matematică, întrebare adresată de jkdnfbnrndndhbbt, 9 ani în urmă

va rog am nevoie pana la ora 14

Anexe:

Răspunsuri la întrebare

Răspuns de elakissup3bs9j
0
1)a)10,08-3,2:0,8=10,08-4=6,08
Sau
 \frac{24}{10}  \times  \frac{42}{10}  -  \frac{32}{10}  \times  \frac{5}{4}  =  \\  \frac{12}{5}  \times  \frac{21}{5}  -  \frac{8}{2}  =

 \frac{252}{25}  - 4 =  \frac{252 - 25 \times 4}{25}  = \\   \frac{252 - 100}{25}  =  \frac{152}{25}  = 6.08
152:25=6,08
150
==20
.......0
.......200
.......200
......===

B)4,5+3,1x2,6=4,5+8,06=12,56

 \frac{45}{10}  +  \frac{31}{10}  \times  \frac{26}{10}  =  \\  \frac{45}{10}  +  \frac{31 \times 13}{5 \times 10}



 \frac{45}{10}  +  \frac{403}{50} =  \frac{5 \times 45 + 403}{50}   \\  =  \frac{225 + 403}{50}  =  \frac{628}{50}  = 12.56


C)34,5+9,11-1,4375+3,1(6)=45,3391(6)


 \frac{345}{10}  +  \frac{911}{100}  -  \frac{92}{10}  \times  \frac{10}{64}  +  \frac{316 - 31}{90}  =


 \frac{345}{10}  +  \frac{911}{100}  -  \frac{23}{16}  +  \frac{285}{90}  =    \\ \frac{69}{2}  +  \frac{911}{100}  -  \frac{23}{16}  +  \frac{57}{18}  =

 \frac{14400 \times 69 + 288 \times 911 - 1800 \times 23 + 57 \times 1600}{28800}


 =  \frac{993600 + 262368 - 41400 + 91200 }{28800}


 \frac{1305768}{28800}  = 45.3391(6)



2)a)25,41-3x1,9=25,41-5,7=19,71

B)11,18:(9,4-2x0, 4)=11,18:(9,4-0,8)=11,18:8,6=1,3
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