va rog am nevoie urgent dau coroana
Răspunsuri la întrebare
Răspuns:
a)BD/CD=2/3 si BC = 45
2CD=3BD
BD+DC=45 rezulta 2CD/3+CD=45 rezulta CD = 27 iar BD = 18
Pitagora
AD^2+DC^2=AC^2
AD^2+BD^2=AB^2
AC^2+AB^2=BC^2
AD^2+DC^2+AD^2+BD^2=BC^2
2AD^2=BC^2-DC^2-BD^2=2025-729-324=972 rezulta AD = radical486 =3radical54=9radical6
AC=radical 486+729=radical1215
AB=radical 486+324= radical810
b) la fel....
c) 9CD=16BD
CD-BD= 7 16BD/9-BD=7 rezulta 7BD=63 rezulta BD = 9 iar CD =16 rezulta BC = 25 si... la fel ca la a)
2)a) AC = radical AD^2+CD^2=....
AD^2=BD*DC rezulta BD = AD^2/CD
BC = CD+BD
AB = radical AD^2+BD^2
b) AD^2=BD*DC
AC=radical AD^2+DC^2
AB=radicalAD^2+BD^2
BC = BD+DC
c) AD= radicalAB^2-BD^2
AD^2=BD*DC rezulta CD = AD^2/BD
BC=BD+DC
AC = radical BC^2-AB^2
3a) AD= radicalAB^2-BD^2
AD^2=BD*DC rezulta CD = AD^2/BD
BC=BD+DC
AC = radical BC^2-AB^2
b) AD=radical AC^2-DC^2
BD = AD^2/DC
BC = BD+DC
AC=radical AD^2+DC^2
AB=radicalAD^2+BD^2
c) identic cu 1a)
Explicație pas cu pas: