Question

va rog Am teza PLEASE in imagine.

Answer 1

 

$\displaystyle\\ \left[2017^0+\left(3^2\right)^{20}:\left(3^{13}\right)^{3}\right]^{30}:8^{20}=\\\\=\left[1+3^{2\times20}:3^{13\times3}\right]^{30}:8^{20}=\\\\=\left[1+3^{40}:3^{39}\right]^{30}:8^{20}=\\\\=\left[1+3^{40-39}\right]^{30}:8^{20}=\\\\=\left[1+3^{1}\right]^{30}:8^{20}=\\\\=\left[1+3\right]^{30}:8^{20}=\\=4^{30}:8^{20}=\\\\=\Big(2^2\Big)^{30}:\Big(2^3\Big)^{20}=\\\\=2^{2\times30}:2^{3\times20}=\\\\=2^{60}:2^{60}=2^{60-60}=2^0=\boxed{\bf1}$