Question

va rog cat mai repede rezolvare completa

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

Răspuns:

$\frac{{3} }{ \sqrt{2} } \div ( \sqrt{6} ) {}^{ - 1} + \sqrt{6} \div ( \frac{1}{ \sqrt{8} } ) {}^{3} \\ \\ = \frac{3}{ \sqrt{2} } \times \sqrt{6} + \sqrt{6} \div \frac{1}{16 \sqrt{2} } \\ \\ = 3 \sqrt{3} + \sqrt{6} \times 16 \sqrt{2} \\ \\ = 3 \sqrt{3} + \sqrt{6 \times 2} \times 16 \\ \\ = 3 \sqrt{3} + \sqrt{12 } \times 6 \\ \\ = 3 \sqrt{3} + 16 \sqrt{12} \\ \\ = 3 \sqrt{3} + 16 \sqrt{2 {}^{2} } \sqrt{3} \\ \\ =3 \sqrt{3} + 16 \times 2 \sqrt{3} \\ \\ = 3 \sqrt{3} + 32 \sqrt{3} \\ \\ = \bf\pink{35 \sqrt{3} }$