Question

Va rog, cat se poate de repede​

Answer 1

$\displaystyle E=16~V;~R=14~\Omega;~r=2~\Omega\\ \\ u=Ir\\ \\ I=\frac{E}{R+r} \Rightarrow I=\frac{16}{14+2} \Rightarrow I=\frac{16}{16} \Rightarrow I=1~A\\ \\ u=1 \cdot 2 \Rightarrow \mathbf{u=2~V}$