Question

Va rog!Chiar nu-mi dau seama :(

Answer 1

Triunghiul BMn este   dreptunghic.Determini  ipotenuzaNM
NM=$\sqrt({ 4^{2} } + 3^{2}) = \sqrt{25} =5$
tΔBNM~ΔBCA conf  teorema  fundamentala   a   asemanarii
$\frac{BN}{Bc} = \frac{5}{15= \frac{1}{3} }$
BC=5*BN=3*3=9
$\frac{BM}{AB} = \frac{4}{AB}=\ \textgreater$
=[tex] \frac{1}{3} [/tex]
AB=4*3=12
P=15+12+9=36