Question

va rog cine ma poate ajuta:(17supra100+2,33)÷5=.....;si b) 17supra15÷ {3,25÷26×1,(3)+5÷2,(7)-[ 3,3(7)÷10,1(3)-1supra3]}

Answer 1

a) (17/100 +2,33):5=
(17/100+233/100):5=
250/100 :5=
250/100 x1/5= 5/10=simplific cu 5=1/2
b) 17/15 : (3,25: 26 x 1,(3) + 5 : 2,(7) - ( 3,3(7) : 10,1(3) - 1/3))=
3,25= 325/100 simplific cu 5= 65/20=simplific cu 5=13/4
1,(3)= 1intreg 3/9= (9x1+3)/9=12/9=simplific cu 3= 4/3
2,(7)=2intreg 7/9= ( 2x9+7)/9=25/9
3,3(7)= 3intreg (37-3)/90= 3intreg 34/90=(3x90+34)/90= 304/90
10,1(3)= 10 intreg (13-1)/90= 10intreg 12/90=(90x10+12)/90=912/90
17/15 : ( 13/4 : 26 x 4/3 + 5 : 25/9 - ( 304/90 : 912/90 - 1/3)=
17/15 : ( 13/4 x 1/26 x4/3 + 5 x9/25 - ( 304/90 x 90/912 -1/3)=
17/15 : ( 1/8 x4/3 + 9/5 - ( 304/912 -1/3)=
17/15 : ( 1/6 + 9/5 - (1/3-1/3)=
17/15 : ( 1/6 +9/5 -0)=
17/15 : ( 1/6+9/5)=
17/15: ( 5/30 + 54/30)=
17/15: 59/30=
17/15 x 30/59=
17/1 x 2/59=
34/59
304/912= simplific cu 4= 76/228simplific cu 76= 1/3