Question

Va rog cine poate pana miercuri sa faca toata fisa asta! Am nevoie urgent de rezolvare, cat mai explicata posibil. Aceste exercitii sunt de chimie, clasa a 9 a. Va multumesc anticipat! ​

Answer 1

1.

densitatea relartiva ro(p) = miu/Vm, Vm = 22,4 L/mol

NO2, miu = 14+2x16 = 46 g/mol

=> p = 46/22,4 = 2,06 g/L

SO3, miu = 32+3x16 = 80 g/mol

=> p = 80/22,4 = 3,57 g/L

2.

aplicam PV = nRT

P= 300 atm, m= 2800 kg, R= 0,082, T= 273+327 = 600K

n = m/M, M.N2 = 2x14 = 28 g/mol

=> PVM = mRT => V= mRT/PM

= 2800x0,082x600/300x28 = 16,4 m3 N2

3.

aplicam formula nr. moli (n) = masa/M = V/Vm = N.molecule/N.A

N.A= 6,022x10la23 molecule

=>

M.Cl2 = 2x35,5 = 71 g/mol

a) V = mxVm/M = 14,2x22,4/71 = 4,8 m3 Cl2

b) V = N.moleculexVm/N.A

= 6,022x10la24x22,4/6,022x10la23 = 224 L O2

4.

aplicam formula nr. moli (n) = masa/M = V/Vm = N.molecule/N.A

a) M.N2 = 14x2 = 28 g/mol

n = m/M = 56/28 = 2 moli N2

b) n = V/Vm = 4,48/22,4 = 0,2 moli H2

5.

aplicam formula nr. moli (n) = masa/M = V/Vm = N.molecule/N.A

a) M.CO2 = 12+2x16 = 44 g/mol

m = MxV/Vm = 44x44,8/22,4 = 88 g CO2

b) M.NH3 = 14+3x1 = 17 g/mol

m = MxV/Vm = 17x67,2/22,4 = 51 g NH3