Question

va rog,cine poate rezolva

Answer 1

$\frac{\sqrt{6} }{2} +\frac{3\sqrt{6} }{2}-2\sqrt{6} =\frac{\sqrt{6} }{2} +\frac{3\sqrt{6} }{2}-\frac{4\sqrt{6} }{2} = \frac{4\sqrt{6}-4\sqrt{6} }{2} =0$

Answer 2

Răspuns:

0

Explicație pas cu pas:

√3/√2+3√6/2-√24=√6/2+3√6/2-2√6=1/2(√6+3√6-4√6)=0