Question

va rog cine stie sa rezolve dau coroana​

Answer 1

a)

$2 \sqrt{3} \times ( \sqrt{6} - \sqrt{5} - \sqrt{6} + \sqrt{5} =0.$

b) 5√2*(√2-√6)-√10+10√3

=√5^2*√2(√2-√6)-√2*√5+√2^2*√5^2*√3

=√10*(√10-√30-1+√30)

=>

$\sqrt{10} \times (10 - 1) = 9 \times \sqrt{10.}$

c)

$2 \sqrt{12} - 2 \sqrt{2} \times ( \sqrt{6} - \sqrt{5}) - \sqrt{40} = 2 \times ( \sqrt{12} - \sqrt{12} - \sqrt{10} - \sqrt{10}) = 0.$

d)

$- \sqrt{32} + \sqrt{216} + 3 \times \times \sqrt{3}( \sqrt{6 } - 2 \sqrt{2}) = 9 \times \sqrt{2} - 4 \times \sqrt{2} = 5 \times \sqrt{2}.$

e) 6-√3/3√3-(2+√3)/2√3-(1+√3)/√3

=

$( - 6 \sqrt{3} - 2 \sqrt{3} - 3 \sqrt{3}) \div 6 \sqrt{3} = - 11 \div 6.$

f)

$8 \times \sqrt{6}.$

g)

$2.$

h)

$\sqrt{5}.$

i)

$4.$