Question

va rog! clasa a șasea​

Answer 1

$(( - 3) {}^{140} \div 9 {}^{69} + ( - 6) {}^{4} \div (3 {}^{3} \times 2 {}^{4} ) + 12) \div ( - 4)$

$(3 {}^{140 } \div 3 {}^{138} + 6 {}^{4} \div (2 \times 6 {}^{3} ) + 12) \div ( - 4)$

$(3 {}^{2} + \frac{6 {}^{4} }{2 \times 6 {}^{3} } + 12) \div ( - 4)$

$(9 + \frac{6}{2} + 12) \div ( - 4)$

$(9 + 3 + 12) \div ( - 4)$

$24 \div ( - 4)$

$- 6$

Answer 2

$\it = [3^{140}:3^{138}+(2^4\cdot3^4):(2^4\cdot3^3)+12]:(-4)=(9+3+12):(-4)=-6$