Question

va rog cu rezolvare :Adevarat sau fals
Precizati care dintre ecuatiile de mai jos admit pe x=2 ca solutie
x²=4
3x²=6
(x+3)²=16
x²=-4
2x²=8
x²-1=15
(x-2)(x+2)+4=4
(2x+1)²=9

Answer 1

a) 2^2=4 (adevarat)

b) 3 ori 2^2 = 6

3 ori 4 = 12 ≠ 6 (fals)

c) (2+3)^2 = 16

5^2 = 25 ≠ 16 (fals)

d) 2^2 = 4 ≠ -4 (fals)

e) 2 ori 2^2 = -4

2 ori 4 = 8 (adevarat)

f) 2^2 - 1 = 15

4 - 1 = 3 ≠ 15 (fals)

g) (2-2)(2+2) + 4 = 4

0 ori 4 + 4 = 4

0 + 4 = 4 (adevarat)

h) (2 ori 2 + 1)^2 = 9

5^2 = 25 ≠ 9 (fals)