Question

va rog cum se demonstreaza:
a) (5a +15b) se divide la 5
b)(27a +21 b )se divide la 3 c)(121a+55b+77c) se divide la 11.

Answer 1

$b) 27a + 21b = 3 (9a + 7b)$
[tex]a) 5a +15b = 5 (a +3b) [/tex]
$c) 121a + 55b + 77c = 11 (11a + 5b + 7c)$