Question

va rog daca ma poate ajuta cineva.dau coroana.​

Answer 1

a) AO=2×BO=10×2=20 cm(T.<30°)

b) P ΔABO=AB+BO+AO

sin <B=AB/AO

AB/20=√3/2

=> AB=10√3 cm

=> P=10(√3+3) cm

c) (BS×AO)/2=(AB×BO)/2

BS×20=10√3×10

BS=100√3:20

BS=5√3 cm

d) AS²=AB²-BS²

AS²=(10√3)²-(5√3)²

AS²=100×3-25×3

AS²=300-75

AS²=225

=> AS=15 cm