Question

va rog!!
dau coroana!!

Answer 1

$a. ( \frac{5}{8} )^{2} x ( \frac{5}{8} )^{9} = ( \frac{5}{8} )^{11}$
$b. ( - \frac{3}{10} )^{8} x ( - \frac{3}{10} )^{9} = ( - \frac{3}{10} )^{17}$
$c. ( - \frac{4}{3} )^{4} x ( - \frac{4}{3} )^{10} = ( - \frac{4}{3} )^{14}$
$d. ( - \frac{5}{2} )^{9} x ( - \frac{4}{3} )^{11} = ( - \frac{4}{3} )^{20}$
$e. [( \frac{1}{2} )^{2}]^{3} = ( \frac{1}{2} )^{8}$
$f. [( - \frac{2}{3} )^{3}]^{5} = ( - \frac{2}{3} )^{243}$
$g. ( \frac{11}{12} )^{25} ( \frac{11}{12} )^{25} = 1$


La a b c si d se aduna puterile , la e si f faci $2^{3}$ respectiv $3^{5}$ iar la g se reduc toti factorii ( 11:11 , 12:12 , 25:25 si iti da $\frac{1}{1}^{1}$ care este egal cu 1)