Question

VA ROG! DAU COROANA....

Answer 1

a+b+c+d=3522

a = (b+c):4,       b+c = a x 4

c:d = 5 r 16,       c = d x 5 +16

d = (a+b):2,        a + b = d x 2

d               |__|

c               |__|__|__|__|__|_16|

dx2 / a+b  |__|__|

3522-16=3506

3506:8 = 434 rest 4 = 434,5 = d

c = 434,5 x 5 + 16

c = 2188,5

a + b = 434,5 x 2 = 869; b = 869 - a

 b+c = a x 4

869 - a + 2188,5 = 4 a

869+2188,5 = 5 a

3057,5 = 5 a

a = 3057,5 : 5

a = 611, 5

a + b = 869

b = 869 - 611,5

b = 257,5

Answer 2

39)

a + b + c + d = 3 522

a = ( b + c ) : 4 ⇒ b + c = 4 × a

c : d = 5 rest 16 ⇒ c = 5 × d + 16

d = ( a + b ) : 2 ⇒ a + b = 2 × d

Inlocuiesc in suma :

( a + b ) + c + d = 3 522

2 × d + 5 × d + 16 + d = 3 522

8 × d = 3 522 - 16

d = 3 506 : 8 → observ ca 3 506 nu se imparte exact la 8

Fiind o problema de clasa a IV -a voi modifica suma cu 3 520 in loc de 3 522 !

( a + b ) + c + d = 3 520

2 × d + 5 × d + 16 + d = 3 520

8 × d = 3 520 - 16 = 3 504

d = 3 504 : 8

d = 438 → al patrulea numar

c = 5 × 438 + 16 = 2 190 + 16 = 2 206 → al treilea nr.

a + b = 2 × 438 = 876 → suma primelor doua numere

3 520 - 876 - 438 = 2 206 → al treilea numar