Question

Va rog dau coroana !!

Answer 1

$x^{2} +8x +16 = (x+4)^{2} \\ x^{2} -6x+9 = (x-3)^{2}\\ x^{2} +2\sqrt{5}x+5 = (x+\sqrt{5} )^{2} \\ 3x^{2} - 2\sqrt{6}xy +2y^{2} = ( \sqrt{3}x- \sqrt{2} y)^{2} \\ 4x^{2} +4 + 8x = ( \sqrt{4}x+2)^{2}\\ 16x^{2} +1 +8x = (4x+1)^{2} \\ x^{4}+4 y^{4}+4 x^{2} y^{2} =  (x^{2}+ 2y^{2})^ {2} \\ x^{4}+ x^{2} +2x^{3} = ( x^{2} +x)^{2}$