Question

Va rog.....:((((
dau coroana​

Answer 1

Răspuns:

E(x)=$\frac{2x+1}{3x-2} : (1-\frac{5x^{2} -3}{9x^{2}-4 }$

$=\frac{2x+1}{3x-2} :\frac{9x^{2}-4-(5x^{2} -3) }{9x^{2} -4}$

$=\frac{2x+1}{3x-2} :\frac{9x^{2} -4-5x^{2} +3}{9x^{2} -4}$

$=\frac{2x+1}{3x-2} :\frac{4x^{2} -1}{9x^{2}-4 }$

$=\frac{2x+1}{3x-2}  . \frac{9x^{2}-4 }{4x^{2}-1 }$

$=\frac{2x+1}{3x-2}. \frac{(3x-2)(3x+2)}{(2x-1)(2x+1)}$

$=\frac{3x+2}{2x-1}$

Explicație:

am demonstrat ca E(x)=$\frac{3x+2}{2x-1}$

sper ca te-am ajutat;)