Question

Vă rog!!!Dau coroană!!!​

Answer 1

Răspuns:

deocarece n par $(-1)^{n+1}$si$(-1)^{2m+1}$vor fii -1

$\frac{(-1)^{n+1}*x+2*(-1)^{2m-1}}{(-1)^{2n+1}*3x-(-1)^{m+2}*2}=\frac{-x+2(-1)^{m+1}}{-3x+(-1)^{2m+3}*2}$

I Daca m numar par →$(-1)^{m+1}$si$(-1)^{2m+3}$ vor fii -1

$\frac{-x+2*(-1)}{-3x-1*2}=\frac{-x-2}{-3x-2}=\frac{x+2}{3x+2}$

x+2|3x+2

x+2|x+2

-------------

2x+4|4x+4

2x+4=4x+4=>2x=0=>x=0

verificare

$\frac{0+2}{3*0+2}=\frac{2}{2}=1$ apartine in Z

II daca m numar impar  => $(-1)^{m+1}$si $(-1)^{2m+3}$ vor fii +1 =>

=>  $\frac{-x+2}{-3x+2}$

-x+2|-3x+2

-x+2|-x+2

-2x+4|-4x+4

-2x+4=-4x+4

2x=0

x=0

Verificare

$\frac{0+2}{-3*0+2}=\frac{2}{2}=1$ apartine in Z

Explicație pas cu pas: