Question

va rog! dau coroana ..culegere clasa a7a .pagina 46

Answer 1

$\it x^2 = 16 \Leftrightarrow \sqrt{x^2} = \sqrt{16} \Leftrightarrow |x| = 4 \Leftrightarrow x=\pm4$

[tex]\it \begin{cases}\it x_1=\it -4 \\ \\ \it x_2 = \it4\end{cases}[/tex]