Question

Va rog dau coroana rezolvati​

Answer 1

Răspuns:

MCa3(PO4)2=3×401+2×31+8×16=310g/mol

m=0,3÷310=93gCa3(PO4)2

MCa(OH)2=40+2×16+2×1=74g/mol

3×74g 310g

3Ca(OH)2+H3PO4 => Ca3(PO4)2+ 6H2O

xg 93g

x=93×3×74/310=calculează