Question

Va rog dau coroana .Sa se calculeze derivatele . 30, 34 , 36, 42, 47 ​. @augustindevian

Answer 1

Răspuns:

Explicație pas cu pas:

30)  f'(x) = 3(3x^2 -5x +1)^2*(6x -5)

34) f'(x) = cos6x *6 = 6cos6x

36) f'(x) = (2x+2)/(2√(x^2 +2x -3)) =

(x+1)/(√(x^2 +2x -3))

42) f'(x) = (2x(x^2 -1) -(x^2+1)*2x)/2√((x^2+1)(x^2 -1)) =

(x^3 -x -x^3 -x)/√((x^2+1)(x^2 -1)) =

-2x/√((x^2+1)(x^2 -1))

47)  f'(x) = 5/(5x +2)