va rog dau coroana!!!!!!! (toate ex va rog)
Răspunsuri la întrebare
Răspuns:
Exercitiul 1.a)
2^4=2x2x2x2=16
3^3=3x3x3=27
7^3=7x7x7=343
8^2=8x8=64
1^2017 (1 ridicat la orice putere da 1)=1
2018^0(orice numar ridicat la puterea 0 da 1)=1
5^4=5x5x5x5=625
2019^1(orice numar ridicat la puterea 1 da acel numar)=2019
11^3=11x11x11=1331
12^2=12x12=144
10^3=10x10x10=1000
101^2=101x101=1010
17^2=17x17=289
5^3=5x5x5=125
2^3=2x2x2=8
67^2=67x67=4489
11^2=11x11=121.
b)
2^3+5^2=8+25=33
3^2-2^3=9-8=1
2^4x5^2=16*25=160
4^3/2^2=64/4=16
3^2x7-1=(mai intai se calculeaza ridicarile la puteri,inmultirile/impartirile iar apoi scaderile/adunarile)=9x7-1=63-1=62
c)
4=2x2=2^2
64=2x2x2x2x2x2=2^6
16=2x2x2x2=2^4
1=2^0
8=2x2x2=2^3
4^2=2x2x2x2=16=2^4
8^3=8x8x8=512=2^9
64^5=64x64x64x64x64=2^30 (deoarece 64=2^6 de 5 ori, 2^30)
d)
1=3^0
81=3x3x3x3=3^4
9=3x3=3^2
27^5=27x27x27x27x27=(deoarece 27= 3^3 de 5 ori va fi 3^15)=3^15
9^16=(3^2)^16=3^32 (daca ridici o putere la alta putere acestea se inmultesc)
81^14=((3^4)^14)=3^56.
2.
a)2^2x2^3x2^0x2=2^6 (deoarece au aceeasi baza,la final se va scrie baza si se vor aduna exponentii) (2 fara exponent inseamna 2^1 si se aduna si el)
b)5^3x5^5x5x5^10=5^19
c)27x3x9x81x2^0=3^3x3x3^2x3^4x3^0=3^10
d)4^2x8^3x2^5x16=((2^2)^2)x((2^3)^3)x2^5x(2^4)=2^19
e)47x47^2x47^5=47^8
f)5^0x5^1x5^2x5^3x5^4=5^10
3. de acum o sa-ti scriu direct,sper ca te-ai prins care este smecheria...
a)2^5+6^3=32+216=248=2^3+31 (am descompus pe 248)
b)25-9=14=2x7
c)8+16+2=26=13x2
d)196-100-64=32=2^5
e)32-8+1=25=5^2
f)343-196-7=140=2^2x5x7
g)1+5+25=31
h)64-27+1=38=2x19
i)8+125+6=139
4.
a)4^3=64
b)5^2=25
c)144-15=119
d)1600+900=2500=5^4x2^2
e)2500-900=1600=2^6x5^2
f)16+9x2x1=16+18=34=2x17
g)25-9+16=32=2^5
h)225-4x9=225-36=189=3^3x7
i) 25+30+9=64=2^6
Sper ca te-am ajutat ♥