Question

va rog ❤❤❤dau coroană ❤❤❤❤❤va multumesc ❤❤❤❤​

Answer 1

Răspuns:

Explicație pas cu pas:

MP║AB, ⇒ΔCMP~ΔCAB. Atunci $\dfrac{CM}{CA}=\dfrac{CP}{CB}$    (1)

MQ║AD, ⇒ΔCMQ~ΔCAD. Atunci  $\dfrac{CM}{CA}= \dfrac{CQ}{CD}=\dfrac{CD-DQ}{CD}=\dfrac{CD}{CD}-\dfrac{DQ}{CD}=1- \dfrac{DQ}{CD}.$     (2)

Din (1)  si (2), ⇒  $\dfrac{CP}{CB}=1-\dfrac{DQ}{CD},~~~deci~~\dfrac{CP}{CB}+\dfrac{DQ}{CD}=1$