Question

va rog dau coroana va rog​

Answer 1

Răspuns:

1)

a) 1+ 2× [ 3+4×( 5+42)] -89=

1+2×( 3+4× 47) -89=

1+ 2×( 3+ 188)-89=

1+2× 564-89=

1+1128-89=

1129-89= 1040

b) 1+2+3+...+99=

[99( 99+1) ]÷2 =

(99×100)÷2= 9900÷2=4950

c) D12 = { 1,2,3,4,6,12}

1+2+3+4+6+12= 28

d) M5= { 5,10,15,20,25,30,35}

5+10+15+20+25+30+35=

5( 1+2+3+4+5+6) = 5× 21= 105

2)

a+b=102

a÷b= 3rest 2》 a= b×3 +2

inlocuim

3xb +2+b= 102

4b+2= 102

4b= 102-2

4b = 100

b = 100 ÷4

b = 25

a= 25×3+2= 77

v: 77+25= 102

3)

41×X +60= 101

41x= 101-60

41x= 41

x= 41:41

x=1

4) 2 la puterea 3×[ 2 +2 la puterea 6: ( 4 la puterea 2 +4 la puterea2)]=

2la puterea 3 × ( 2 + 2 la puterea 6 ÷ 32) =

2 la puterea 3× ( 2 + 2 la puterea 6 ÷ 2 la puterea 5) =

2 la puterea 3 ×( 2+ 2)

8×4=32